1 kg of water at 100^° C is converted into steam at 100^° C by boiling at atmospheric pressure. The volume of water changes from 1.00 × 10^-3 m^3 as…

$\displaystyle 1$ kg of water at $\displaystyle 100^{\circ} \mathrm{C}$ is converted into steam at $\displaystyle 100^{\circ} \mathrm{C}$ by boiling at atmospheric pressure. The volume of water changes from $\displaystyle 1.00 \times 10^{-3} \mathrm{~m}^3$ as a liquid to $\displaystyle 1.671 \mathrm{~m}^3$ as steam. The change in internal energy of the system during the process will be (Given latent heat of vaporisaiton $\displaystyle =2257 \mathrm{~kJ} / \mathrm{kg}$, Atmospheric pressure = $\displaystyle 1 \times 10^5 \mathrm{~Pa}$ )