Mathematics · 2013
JEE Main · 9 April 2013, Shift 1 · Q72
The values of ' a ' for which one root of the equation x^2-( a +1) x+ a^2+ a -8=0 exceeds 2 and the other is lesser than 2, are given by:
The values of ' a ' for which one root of the equation $\displaystyle x^2-(\mathrm{a}+1) x+\mathrm{a}^2+\mathrm{a}-8=0$ exceeds $\displaystyle 2$ and the other is lesser than $\displaystyle 2$, are given by :
Official answer
(3)
$\displaystyle -2<a<3$
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JEE Main 2013 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.