Mathematics · 2017
JEE Main · 9 April 2017, Shift 1 · Q70
The value of k for which the function f(x)= {(4/5)^((tan 4 x)/(tan 5 x)), 0<x<(π)/2; k +2/5, x=(π)/2} is continuous at x=(π)/2, is:
The value of k for which the function
$$f(x)= \begin{cases}\left(\frac{4}{5}\right)^{\frac{\tan 4 x}{\tan 5 x}}, & 0<x<\frac{\pi}{2} \\ \mathrm{k}+\frac{2}{5}, & x=\frac{\pi}{2}\end{cases}
$$
is continuous at $\displaystyle x=\frac{\pi}{2}$, is :
Official answer
(3)
$\displaystyle \frac{3}{5}$
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JEE Main 2017 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.