Mathematics · 2026
JEE Main · 23 January 2026, Shift 1 · Q7
The value of (^100 C_50)/51+(^100 C_51)/52+….+(^100 C_100)/101 is:
The value of $\displaystyle \frac{{ }^{100} C_{50}}{51}+\frac{{ }^{100} C_{51}}{52}+\ldots .+\frac{{ }^{100} C_{100}}{101}$ is :
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle \frac{2^{100}}{101}$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.