Mathematics · 2021
JEE Main · 17 March 2021, Shift 1 · Q64
The system of equations k x+y+z=1, x+ k y+z= k and x+y+z k = k^2 has no solution if k is equal to:
The system of equations $\displaystyle \mathrm{k} x+y+z=1, x+\mathrm{k} y+z=\mathrm{k}$ and $\displaystyle x+y+z \mathrm{k}=\mathrm{k}^2$ has no solution if k is equal to:
Official answer
(4)
$\displaystyle -2$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.