Mathematics · 2026
JEE Main · 6 April 2026, Shift 2 · Q6
The sum 1+1/2(1^2+2^2)+1/3(1^2+2^2+3^2)+…. upto 10 terms is equal to:
The sum $\displaystyle 1+\frac{1}{2}\left(1^2+2^2\right)+\frac{1}{3}\left(1^2+2^2+3^2\right)+\ldots$. upto $\displaystyle 10$ terms is equal to :
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle \frac{315}{2}$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.