Mathematics · 2026
JEE Main · 2 April 2026, Shift 2 · Q5
The sum 1^3/1+(1^3+2^3)/(1+3)+(1^3+2^3+3^3)/(1+3+5)+⋯ up to 8 terms, is:
The sum $\displaystyle \frac{1^3}{1}+\frac{1^3+2^3}{1+3}+\frac{1^3+2^3+3^3}{1+3+5}+\cdots$ up to $\displaystyle 8$ terms, is :
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 71$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.