Mathematics · 2023
JEE Main · 10 April 2023, Shift 1 · Q10
The slope of tangent at any point (x, y) on a curve y=y(x) is (x^2+y^2)/(2 x y), x>0. If y(2)=0, then a value of y(8) is
The slope of tangent at any point $\displaystyle (x, y)$ on a curve $\displaystyle y=y(x)$ is $\displaystyle \frac{x^2+y^2}{2 x y}, x>0$. If $\displaystyle y(2)=0$, then a value of $\displaystyle y(8)$ is
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 4 \sqrt{3}$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.