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Mathematics · 2022

JEE Main · 30 June 2022, Shift 1 · Q29

The probability distribution of X is: For the minimum possible value of d, sixty times the mean of X is equal to \ \ \ \.

The probability distribution of X is :
X$\displaystyle 0$$\displaystyle 1$$\displaystyle 2$$\displaystyle 3$
P(X)$\displaystyle \frac{1-\mathrm{d}}{4}$$\displaystyle \frac{1+2 \mathrm{~d}}{4}$$\displaystyle \frac{1-4 \mathrm{~d}}{4}$$\displaystyle \frac{1+3 \mathrm{~d}}{4}$
For the minimum possible value of d, sixty times the mean of X is equal to \_\_\_\_.
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.