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Mathematics · 2026

JEE Main · 28 January 2026, Shift 2 · Q8

The probability distribution of a random variable X is given below: If E ( X )=263/15, then P ( X <20) is equal to:

The probability distribution of a random variable X is given below :
X4k$\displaystyle \frac{30}{7} \mathrm{k}$$\displaystyle \frac{32}{7} \mathrm{k}$$\displaystyle \frac{34}{7} \mathrm{k}$$\displaystyle \frac{36}{7} \mathrm{k}$$\displaystyle \frac{38}{7} \mathrm{k}$$\displaystyle \frac{40}{7} \mathrm{k}$6k
P(X)$\displaystyle \frac{2}{15}$$\displaystyle \frac{1}{15}$$\displaystyle \frac{2}{15}$$\displaystyle \frac{1}{5}$$\displaystyle \frac{1}{15}$$\displaystyle \frac{2}{15}$$\displaystyle \frac{1}{5}$$\displaystyle \frac{1}{15}$
If $\displaystyle \mathrm{E}(\mathrm{X})=\frac{263}{15}$, then $\displaystyle \mathrm{P}(\mathrm{X}<20)$ is equal to :
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.