Mathematics · 2026
JEE Main · 28 January 2026, Shift 2 · Q8
The probability distribution of a random variable X is given below: If E ( X )=263/15, then P ( X <20) is equal to:
The probability distribution of a random variable X is given below :
If $\displaystyle \mathrm{E}(\mathrm{X})=\frac{263}{15}$, then $\displaystyle \mathrm{P}(\mathrm{X}<20)$ is equal to :
| X | 4k | $\displaystyle \frac{30}{7} \mathrm{k}$ | $\displaystyle \frac{32}{7} \mathrm{k}$ | $\displaystyle \frac{34}{7} \mathrm{k}$ | $\displaystyle \frac{36}{7} \mathrm{k}$ | $\displaystyle \frac{38}{7} \mathrm{k}$ | $\displaystyle \frac{40}{7} \mathrm{k}$ | 6k |
| P(X) | $\displaystyle \frac{2}{15}$ | $\displaystyle \frac{1}{15}$ | $\displaystyle \frac{2}{15}$ | $\displaystyle \frac{1}{5}$ | $\displaystyle \frac{1}{15}$ | $\displaystyle \frac{2}{15}$ | $\displaystyle \frac{1}{5}$ | $\displaystyle \frac{1}{15}$ |
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle \frac{11}{15}$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.