Mathematics · 2026
JEE Main · 21 January 2026, Shift 2 · Q3
The positive integer n, for which the solutions of the equation x(x+2)+(x+2)(x+4)+⋯+(x+2 n -2)(x+2 n )=(8 n)/3 are two consecutive even integers, is:
The positive integer n, for which the solutions of the equation
$\displaystyle x(x+2)+(x+2)(x+4)+\cdots+(x+2 \mathrm{n}-2)(x+2 \mathrm{n})=\frac{8 \mathrm{n}}{3}$ are two consecutive even integers, is :
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 3$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.