Mathematics · 2021
JEE Main · 26 August 2021, Shift 2 · Q72
The point P (-2 √ 6, √ 3 ) lies on the hyperbola x^2/(a^2)-y^2/(b^2)=1 having eccentricity (√ 5)/2. If the tangent and normal at P to the hyperbola…
The point $\displaystyle \mathrm{P}(-2 \sqrt{6}, \sqrt{3})$ lies on the hyperbola $\displaystyle \frac{x^2}{\mathrm{a}^2}-\frac{y^2}{\mathrm{~b}^2}=1$ having eccentricity $\displaystyle \frac{\sqrt{5}}{2}$. If the tangent and normal at P to the hyperbola intersect its conjugate axis at the points Q and R respectively, then QR is equal to :
Official answer
(4)
$\displaystyle 6 \sqrt{3}$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.