Mathematics · 2018
JEE Main · 16 April 2018, Shift 1 · Q65
The number of values of k for which the system of linear equations, ( k +2) x+10 y= k; k x+( k +3) y= k -1 has no solution, is:
The number of values of k for which the system of linear equations,
$$\begin{aligned}
& (\mathrm{k}+2) x+10 y=\mathrm{k} \\
& \mathrm{k} x+(\mathrm{k}+3) y=\mathrm{k}-1
\end{aligned}
$$
has no solution, is :
Official answer
(1)
$\displaystyle 1$
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JEE Main 2018 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.