Offline paper
Mathematics · 2013
JEE Main 2013 · 2013-04-07 Offline · Q11
The number of values of k, for which the system of equations: ( k +1) x+8 y=4 k; k x+( k +3) y=3 k -1 has no solution, is:
The number of values of $\displaystyle \mathbf{k}$, for which the system of equations :
$$\begin{aligned}
& (\mathrm{k}+1) x+8 y=4 \mathrm{k} \\
& \mathrm{k} x+(\mathrm{k}+3) y=3 \mathrm{k}-1
\end{aligned}
$$
has no solution, is :
Official answer
(3)
$\displaystyle 1$
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JEE Main 2013 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.