Mathematics · 2024
JEE Main · 5 April 2024, Shift 2 · Q21
The number of solutions of sin^2 x+(2+2 x-x^2) sin x-3(x-1)^2=0, where -π ≤ x ≤ π, is ____.
The number of solutions of $\displaystyle \sin ^2 x+\left(2+2 x-x^2\right) \sin x-3(x-1)^2=0$, where $\displaystyle -\pi \leq x \leq \pi$, is
$\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
2
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.