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Mathematics · 2022

JEE Main · 29 July 2022, Shift 2 · Q24

The number of natural numbers lying between 1012 and 23421 that can be formed using the digits 2, 3, 4, 5, 6 (repetition of digits is not allowed)…

The number of natural numbers lying between $\displaystyle 1012$ and $\displaystyle 23421$ that can be formed using the digits $\displaystyle 2$, $\displaystyle 3$, $\displaystyle 4$, $\displaystyle 5$, $\displaystyle 6$ (repetition of digits is not allowed) and divisible by $\displaystyle 55$ is \_\_\_\_.
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.