Mathematics · 2019
JEE Main · 9 January 2019, Shift 2 · Q66
The number of natural numbers less than 7,000 which can be formed by using the digits 0, 1, 3, 7, 9 (repitition of digits allowed) is equal to:
The number of natural numbers less than $\displaystyle 7,000$ which can be formed by using the digits $\displaystyle 0$, $\displaystyle 1$, $\displaystyle 3$, $\displaystyle 7$, $\displaystyle 9$ (repitition of digits allowed) is equal to :
Official answer
(3)
$\displaystyle 374$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.