Mathematics · 2019
JEE Main · 8 April 2019, Shift 2 · Q66
The number of four-digit numbers strictly greater than 4321 that can be formed using the digits 0, 1, 2, 3, 4, 5 (repetition of digits is allowed) is:
The number of four-digit numbers strictly greater than $\displaystyle 4321$ that can be formed using the digits $\displaystyle 0$, $\displaystyle 1$, $\displaystyle 2$, $\displaystyle 3$, $\displaystyle 4$, $\displaystyle 5$ (repetition of digits is allowed) is :
Official answer
(1)
$\displaystyle 310$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.