Mathematics · 2022
JEE Main · 25 July 2022, Shift 1 · Q4
The number of θ ∈(0,4 π) for which the system of linear equations 3( sin 3 θ) x-y+z=2; 3( cos 2 θ) x+4 y+3 z=3; 6 x+7 y+7 z=9 has no solution, is:
The number of $\displaystyle \theta \in(0,4 \pi)$ for which the system of linear equations
$$\begin{aligned}
& 3(\sin 3 \theta) x-y+z=2 \\
& 3(\cos 2 \theta) x+4 y+3 z=3 \\
& 6 x+7 y+7 z=9
\end{aligned}
$$
has no solution, is :
Official answer
(2)
$\displaystyle 7$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.