Mathematics · 2022
JEE Main · 26 July 2022, Shift 1 · Q16
The mean and variance of a binomial distribution are α and (α)/3 respectively. If P ( X =1)=4/243, then P ( X =4 or 5 ) is equal to:
The mean and variance of a binomial distribution are $\displaystyle \alpha$ and $\displaystyle \frac{\alpha}{3}$ respectively. If $\displaystyle \mathrm{P}(\mathrm{X}=1)=\frac{4}{243}$, then $\displaystyle \mathrm{P}(\mathrm{X}=4$ or $\displaystyle 5 )$ is equal to :
Official answer
(3)
$\displaystyle \frac{16}{27}$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.