Mathematics · 2021
JEE Main · 16 March 2021, Shift 2 · Q77
The maximum value of f(x)= |sin^2 x, 1+ cos^2 x, cos 2 x; 1+ sin^2 x, cos^2 x, cos 2 x; sin^2 x, cos^2 x, sin 2 x|, x ∈ R is:
The maximum value of $\displaystyle f(x)=\left|\begin{array}{ccc}\sin ^2 x & 1+\cos ^2 x & \cos 2 x \\ 1+\sin ^2 x & \cos ^2 x & \cos 2 x \\ \sin ^2 x & \cos ^2 x & \sin 2 x\end{array}\right|, x \in \mathbf{R}$ is :
Official answer
(1)
$\displaystyle \sqrt{5}$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.