Mathematics · 2021
JEE Main · 25 February 2021, Shift 1 · Q89
The locus of the point of intersection of the lines (√ 3 ) k x+ k y-4 √ 3 =0 and √ 3 x-y-4(√ 3 ) k =0 is a conic, whose eccentricity is \ \ \ \.
The locus of the point of intersection of the lines $\displaystyle (\sqrt{3}) \mathrm{k} x+\mathrm{k} y-4 \sqrt{3}=0$ and $\displaystyle \sqrt{3} x-y-4(\sqrt{3}) \mathrm{k}=0$ is a conic, whose eccentricity is \_\_\_\_.
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.