Mathematics · 2021
JEE Main · 16 March 2021, Shift 1 · Q78
The locus of the midpoints of the chord of the circle, x^2+y^2=25 which is tangent to the hyperbola, x^2/9-y^2/16=1 is:
The locus of the midpoints of the chord of the circle, $\displaystyle x^2+y^2=25$ which is tangent to the hyperbola, $\displaystyle \frac{x^2}{9}-\frac{y^2}{16}=1$ is :
Official answer
(3)
$\displaystyle \left(x^2+y^2\right)^2-9 x^2+16 y^2=0$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.