Mathematics · 2022
JEE Main · 28 July 2022, Shift 2 · Q65
The function f: R → R defined by f(x)= lim_n → ∞ (cos (2 π x)-x^2 n sin (x-1))/(1+x^2 n+1-x^2 n) is continuous for all x in:
The function $\displaystyle f: \mathbb{R} \rightarrow \mathbb{R}$ defined by $\displaystyle f(x)=\lim _{n \rightarrow \infty} \frac{\cos (2 \pi x)-x^{2 n} \sin (x-1)}{1+x^{2 n+1}-x^{2 n}}$ is continuous for all $\displaystyle x$ in :
Official answer
(2)
$\displaystyle \mathbb{R}-\{-1,1\}$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.