Mathematics · 2024
JEE Main · 8 April 2024, Shift 1 · Q5
The equations of two sides AB and AC of a triangle ABC are 4 x+y=14 and 3 x-2 y=5, respectively. The point (2,-4/3) divides the third side BC…
The equations of two sides AB and AC of a triangle ABC are $\displaystyle 4 x+y=14$ and $\displaystyle 3 x-2 y=5$, respectively. The point $\displaystyle \left(2,-\frac{4}{3}\right)$ divides the third side BC internally in the ratio $\displaystyle 2: 1$. the equation of the side $\displaystyle B C$ is
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle x+3 y+2=0$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.