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Mathematics · 2013
JEE Main 2013 · 2013-04-07 Offline · Q5
The equation of the circle passing through the foci of the ellipse x^2/16+y^2/9=1, and having centre at (0,3) is:
The equation of the circle passing through the foci of the ellipse $\displaystyle \frac{x^2}{16}+\frac{y^2}{9}=1$, and having centre at $\displaystyle (0,3)$ is :
Official answer
(2)
$\displaystyle x^2+y^2-6 y-7=0$
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JEE Main 2013 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.