Mathematics · 2019
JEE Main · 12 January 2019, Shift 2 · Q80
The equation of a tangent to the parabola, x^2=8 y, which makes an angle θ with the positive direction of x -axis, is:
The equation of a tangent to the parabola, $\displaystyle x^2=8 y$, which makes an angle $\displaystyle \theta$ with the positive direction of $\displaystyle x$-axis, is :
Official answer
(2)
$\displaystyle x=y \cot \theta+2 \tan \theta$
More from Parabola
- Let the tangent to the curve x^2+2 x-4 y+9=0 at the point P(1,3) on it meet the y -axis at A. Let the line passing through P and parallel to the line…2023
- The ordinates of the points P and Q on the parabola with focus (3,0) and directrix x=-3 are in the ratio 3: 1. If R(α, β) is the point of…2023
- The tangents at the points A(1,3) and B(1,-1) on the parabola y^2-2 x-2 y=1 meet at the point P. Then the area (in unit ^2 ) of the triangle P A B is:2022
- Two parabolas have the same focus (4,3) and their directrices are the x -axis and the y -axis, respectively. If these parabolas intersects at the…2025
- Let a line y=m x( m>0) intersect the parabola, y^2=x at a point P, other than the origin. Let the tangent to it at P meet the x -axis at the point Q.…2020
- Let the image of parabola x^2=4 y, in the line x-y=1 be (y+a)^2=b(x-c), a, b, c ∈ N. Then a+b+c is equal to2026
- Let P(α, β) be a point on the parabola y^2=4 x. If P also lies on the chord of the parabola x^2=8 y whose mid point is (1, 5/4), then (α-28)(β-8) is…2024
- Let P_1 be a parabola with vertex (3,2) and focus (4,4) and P_2 be its mirror image with respect to the line x+2 y=6. Then the directrix of P_2 is…2022
JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.