Mathematics · 2019
JEE Main · 10 January 2019, Shift 1 · Q82
The equation of a tangent to the hyperbola 4 x^2-5 y^2=20 parallel to the line x-y=2 is:
The equation of a tangent to the hyperbola $\displaystyle 4 x^2-5 y^2=20$ parallel to the line $\displaystyle x-y=2$ is :
Official answer
(1)
$\displaystyle x-y+1=0$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.