Mathematics · 2019
JEE Main · 12 April 2019, Shift 2 · Q81
The equation of a common tangent to the curves, y^2=16 x and x y=-4, is:
The equation of a common tangent to the curves, $\displaystyle y^2=16 x$ and $\displaystyle x y=-4$, is :
Official answer
(4)
$\displaystyle x-y+4=0$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.