Mathematics · 2023
JEE Main · 31 January 2023, Shift 2 · Q63
The equation e^4 x+8 e^3 x+13 e^2 x-8 e^x+1=0, x ∈ R has:
The equation $\displaystyle \mathrm{e}^{4 x}+8 \mathrm{e}^{3 x}+13 \mathrm{e}^{2 x}-8 \mathrm{e}^x+1=0, x \in \mathbb{R}$ has:
Official answer
From NTA’s final answer key for this paper.
(3)
two solutions and both are negative
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.