Mathematics · 2026
JEE Main · 6 April 2026, Shift 2 · Q11
The eccentricity of an ellipse E with centre at the origin O is (√ 3)/2 and its directrices are x= ± (4 √ 6)/3. Let H: x^2/(a^2)-y^2/(b^2)=1 be a…
The eccentricity of an ellipse E with centre at the origin O is $\displaystyle \frac{\sqrt{3}}{2}$ and its directrices are $\displaystyle x= \pm \frac{4 \sqrt{6}}{3}$. Let $\displaystyle \mathrm{H}: \frac{x^2}{\mathrm{a}^2}-\frac{y^2}{\mathrm{~b}^2}=1$ be a hyperbola whose eccentricity is equal to the length of semi-major axis of E , and whose length of latus rectum is equal to the length of minor axis of E . Then the distance between the foci of H is :
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle \frac{8}{7}$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.