Mathematics · 2024
JEE Main · 29 January 2024, Shift 2 · Q13
The distance of the point (2,3) from the line 2 x-3 y+28=0, measured parallel to the line √ 3 x-y+1=0, is equal to
The distance of the point $\displaystyle (2,3)$ from the line $\displaystyle 2 x-3 y+28=0$, measured parallel to the line $\displaystyle \sqrt{3} x-y+1=0$, is equal to
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 4+6 \sqrt{3}$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.