Mathematics · 2023
JEE Main · 25 January 2023, Shift 1 · Q72
The distance of the point (6,-2 √ 2 ) from the common tangent y = mx + c, m >0, of the curves x=2 y^2 and x=1+y^2 is:
The distance of the point $\displaystyle (6,-2 \sqrt{2})$ from the common tangent $\displaystyle \mathrm{y}=\mathrm{mx}+\mathrm{c}, \mathrm{m}>0$, of the curves $\displaystyle x=2 y^2$ and $\displaystyle x=1+y^2$ is:
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 5$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.