Mathematics · 2014
JEE Main · 19 April 2014, Shift 1 · Q78
The circumcentre of a triangle lies at the origin and its centroid is the mid point of the line segment joining the points ( a^2+1, a^2+1) and (2…
The circumcentre of a triangle lies at the origin and its centroid is the mid point of the line segment joining the points $\displaystyle \left(\mathrm{a}^2+1, \mathrm{a}^2+1\right)$ and $\displaystyle (2 \mathrm{a},-2 \mathrm{a}), \mathrm{a} \neq 0$. Then for any a, the orthocentre of this triangle lies on the line :
Official answer
(4)
$\displaystyle (a-1)^2 x-(a+1)^2 y=0$
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JEE Main 2014 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.