Mathematics · 2026
JEE Main · 23 January 2026, Shift 2 · Q20
The area of the region enclosed between the circles x^2+y^2=4 and x^2+(y-2)^2=4 is:
The area of the region enclosed between the circles $\displaystyle x^2+y^2=4$ and $\displaystyle x^2+(y-2)^2=4$ is:
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle \frac{2}{3}(4 \pi-3 \sqrt{3})$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.