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Mathematics · 2026

JEE Main · 23 January 2026, Shift 1 · Q11

Number of solutions of √ 3 cos 2 θ+8 cos θ+3 √ 3 =0, θ ∈[-3 π, 2 π] is:

Number of solutions of $\displaystyle \sqrt{3} \cos 2 \theta+8 \cos \theta+3 \sqrt{3}=0, \theta \in[-3 \pi, 2 \pi]$ is :
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.