If |a-b-c, 2 a, 2 a; 2 b, b-c-a, 2 b; 2 c, 2 c, c-a-b|; =(a+b+c) (x+a+b+c)^2, x ≠ 0 and a+b+c ≠ 0, then x is equal to:

$$\begin{aligned} & \text { If }\left|\begin{array}{ccc} a-b-c & 2 a & 2 a \\ 2 b & b-c-a & 2 b \\ 2 c & 2 c & c-a-b \end{array}\right| \\ & =(a+b+c) \quad(x+a+b+c)^2, \quad x \neq 0 \text { and } \\ & a+b+c \neq 0, \text { then } x \text { is equal to : } \end{aligned} $$