Mathematics · 2021
JEE Main · 27 August 2021, Shift 2 · Q64
Let A = ([x+1], [x+2], [x+3]; [x], [x+3], [x+3]; [x], [x+2], [x+4]), where [ t ] denotes the greatest integer less than or equal to t. If det ( A…
Let $\displaystyle \mathrm{A}=\left(\begin{array}{ccc}{[x+1]} & {[x+2]} & {[x+3]} \\ {[x]} & {[x+3]} & {[x+3]} \\ {[x]} & {[x+2]} & {[x+4]}\end{array}\right)$, where $\displaystyle [\mathrm{t}]$ denotes the greatest integer less than or equal to t . If $\displaystyle \operatorname{det}(\mathrm{A})=192$, then the set of values of $\displaystyle x$ is the interval :
Official answer
(3)
[$\displaystyle 62$, $\displaystyle 63$)
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.