Mathematics · 2021
JEE Main · 26 August 2021, Shift 2 · Q64
Let A = (1, 0, 0; 0, 1, 1; 1, 0, 0). Then A^2025- A^2020 is equal to:
Let $\displaystyle \mathrm{A}=\left(\begin{array}{lll}1 & 0 & 0 \\ 0 & 1 & 1 \\ 1 & 0 & 0\end{array}\right)$. Then $\displaystyle \mathrm{A}^{2025}-\mathrm{A}^{2020}$ is equal to :
Official answer
(3)
$\displaystyle \mathrm{A}^6-\mathrm{A}$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.