Mathematics · 2023
JEE Main · 24 January 2023, Shift 2 · Q88
Let S={θ ∈[0,2 π): tan (π cos θ)+ tan (π sin θ)=0}. Then Σ_θ ∈ S sin^2(θ+(π)/4) is equal to ____.
Let $\displaystyle S=\{\theta \in[0,2 \pi): \tan (\pi \cos \theta)+\tan (\pi \sin \theta)=0\}$.
Then $\displaystyle \sum_{\theta \in \mathrm{S}} \sin ^2\left(\theta+\frac{\pi}{4}\right)$ is equal to $\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
2
More from Trigonometric Equations
- The number of solutions of the equation (4-√3) sin x-2 √3 cos^2 x=-4/(1+√3), x ∈[-2 π, (5 π)/2] is2025
- The number of elements in the set S={θ ∈[0,2 π]: 3 cos^4 θ-5 cos^2 θ-2 sin^6 θ+2=0} is2023
- The number of solutions, of the equation e^sin x-2 e^- sin x=2, is:2024
- Suppose θ ∈[0, (π)/4] is a solution of 4 cos θ-3 sin θ=1. Then cos θ is equal to:2024
- If S={θ ∈[-π, π]: cos θ cos (5 θ)/2= cos 7 θ cos (7 θ)/2}, then n(S) is equal to ____.2026
- The sum of all values of θ ∈[0,2 π] satisfying 2 sin^2 θ= cos 2 θ and 2 cos^2 θ=3 sin θ is2025
- The number of solutions of the equation 2 x+3 tan x=π, x ∈[-2 π, 2 π]-{ ± (π)/2, ± (3 π)/2} is:2025
- The number of solutions of the equation 4 sin^2 x-4 cos^3 x+9-4 cos x=0; x ∈[-2 π, 2 π] is:2024
JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.