Mathematics · 2023
JEE Main · 30 January 2023, Shift 1 · Q70
Let the solution curve y=y(x) of the differential equation (d y)/(d x)-(3 x^5 tan^-1(x^3))/((1+x^6)^3 / 2) y=2 x exp {(x^3- tan^-1 x^3)/(√((1+x^6)))}…
Let the solution curve $\displaystyle y=y(x)$ of the differential equation
$$\frac{\mathrm{d} y}{\mathrm{~d} x}-\frac{3 x^5 \tan ^{-1}\left(x^3\right)}{\left(1+x^6\right)^{3 / 2}} y=2 x \exp \left\{\frac{x^3-\tan ^{-1} x^3}{\sqrt{\left(1+x^6\right)}}\right\} \text { pass through the origin. Then } y(1) \text { is equal to : }
$$
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle \exp \left(\frac{4-\pi}{4 \sqrt{2}}\right)$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.