Mathematics · 2021
JEE Main · 4 August 2021, Shift 2 · Q74
Let the normal at any point of hyperbola x^2/a^2-y^2/b^2=1 intersect the coordinate axes at points P and Q. Then the locus of the mid-point of PQ is:
Let the normal at any point of hyperbola $\displaystyle \frac{x^2}{a^2}-\frac{y^2}{b^2}=1$ intersect the coordinate axes at points P and Q . Then the locus of the mid-point of PQ is :
Official answer
(4)
$\displaystyle 4\left(a^2 x^2-b^2 y^2\right)=\left(a^2+b^2\right)$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.