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Mathematics · 2022

JEE Main · 24 June 2022, Shift 2 · Q29

Let the hyperbola H: x^2/a^2-y^2=1 and the ellipse E: 3 x^2+4 y^2=12 be such that the length of latus rectum of H is equal to the length of latus…

Let the hyperbola $\displaystyle H: \frac{x^2}{a^2}-y^2=1$ and the ellipse $\displaystyle E: 3 x^2+4 y^2=12$ be such that the length of latus rectum of $\displaystyle H$ is equal to the length of latus rectum of $\displaystyle E$. If $\displaystyle e_H$ and $\displaystyle e_E$ are the eccentricities of $\displaystyle H$ and $\displaystyle E$ respectively, then the value of $\displaystyle 12\left(e_H^2+e_E^2\right)$ is equal to \_\_\_\_.
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.