Mathematics · 2023
JEE Main · 13 April 2023, Shift 2 · Q13
Let the centre of a circle C be (α, β) and its radius r<8. Let 3 x+4 y=24 and 3 x-4 y=32 be two tangents and 4 x+3 y=1 be a normal to C. Then (α-β+r)…
Let the centre of a circle $\displaystyle C$ be $\displaystyle (\alpha, \beta)$ and its radius $\displaystyle r<8$. Let $\displaystyle 3 x+4 y=24$ and $\displaystyle 3 x-4 y=32$ be two tangents and $\displaystyle 4 x+3 y=1$ be a normal to C. Then $\displaystyle (\alpha-\beta+r)$ is equal to
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 7$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.