SolveItJEE Main
Mathematics · 2026

JEE Main · 23 January 2026, Shift 1 · Q25

Let the area of the region bounded by the curve y= max { sin x, cos x}, lines x=0, x=(3 π)/2, and the x -axis be A. Then, A + A^2 is equal to ____.

Let the area of the region bounded by the curve $\displaystyle y=\max \{\sin x, \cos x\}$, lines $\displaystyle x=0, x=\frac{3 \pi}{2}$, and the $\displaystyle x$-axis be A . Then, $\displaystyle \mathrm{A}+\mathrm{A}^2$ is equal to $\displaystyle \_\_\_\_$.
ShareWhatsAppTelegram

More from Area Under the Curve

JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.