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Mathematics · 2026

JEE Main · 23 January 2026, Shift 2 · Q22

Let S denote the set of 4-digit numbers a b c d such that a>b>c>d and P denote the set of 5 -digit numbers having product of its digits equal to 20.…

Let S denote the set of $\displaystyle 4$-digit numbers $\displaystyle a b c d$ such that $\displaystyle a>b>c>d$ and P denote the set of $\displaystyle 5$ -digit numbers having product of its digits equal to $\displaystyle 20$ . Then $\displaystyle n(\mathrm{~S})+n(\mathrm{P})$ is equal to $\displaystyle \_\_\_\_$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.