Mathematics · 2024
JEE Main · 31 January 2024, Shift 1 · Q2
Let S be the set of postive integral values of a for which (a x^2+2(a+1) x+9 a+4)/(x^2-8 x+32)<0, ∀ x ∈ R. Then, the number of elements in S is:
Let S be the set of postive integral values of $\displaystyle a$ for which $\displaystyle \frac{a x^2+2(a+1) x+9 a+4}{x^2-8 x+32}<0, \forall x \in \mathbb{R}$. Then, the number of elements in S is :
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 0$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.