Mathematics · 2018
JEE Main · 15 April 2018, Shift 1 · Q65
Let S be the set of all real values of k for which the system of linear equations x+y+z=2; 2 x+y-z=3; 3 x+2 y+ k z=4 has a unique solution. Then S is:
Let S be the set of all real values of k for which the system of linear equations
$$\begin{aligned}
& x+y+z=2 \\
& 2 x+y-z=3 \\
& 3 x+2 y+\mathrm{k} z=4
\end{aligned}
$$
has a unique solution. Then S is :
Official answer
(4)
equal to $\displaystyle \mathbf{R}-\{0\}$
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JEE Main 2018 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.