Mathematics · 2020
JEE Main · 3 September 2020, Shift 2 · Q70
Let p, q, r be three statements such that the truth value of ( p ∧ q ) →(∼ q r ) is F. Then the truth values of p, q, r are respectively:
Let p, q, r be three statements such that the truth value of $\displaystyle (\mathrm{p} \wedge \mathrm{q}) \rightarrow(\sim \mathrm{q} \vee \mathrm{r})$ is F . Then the truth values of $\displaystyle \mathrm{p}, \mathrm{q}, \mathrm{r}$ are respectively :
Official answer
(3)
T, T, F
More from Mathematical Reasoning
- The statement ∼[p (∼(p ∧ q))] is equivalent to2023
- Which of the following is a tautology?2020
- Which of the following statements is a tautology?2023
- Let Δ, ∇ ∈{∧, } be such that (p → q) Δ(p ∇ q) is a tautology. Then2023
- (p ∧ r) ⇔(p ∧(∼ q)) is equivalent to (∼ p) when r is2022
- Contrapositive of the statement: 'If a function f is differentiable at a, then it is also continuous at a', is:2020
- For the statements p and q, consider the following compound statements: (∼ q ∧(p → q)) → ∼ p ((p q) ∧ ∼ p) → q Then which of the following statements…2021
- If p, q and r are three propositions, then which of the following combination of truth values of p, q and r makes the logical expression {(p q) ∧((∼…2023
JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.