Mathematics · 2018
JEE Main · 16 April 2018, Shift 1 · Q62
Let p, q and r be real numbers ( p ≠ q, r ≠ 0), such that the roots of the equation 1/(x+ p)+1/(x+ q)=1/r are equal in magnitude but opposite in…
Let p, q and r be real numbers $\displaystyle (\mathrm{p} \neq \mathrm{q}, \mathrm{r} \neq 0)$, such that the roots of the equation $\displaystyle \frac{1}{x+\mathrm{p}}+\frac{1}{x+\mathrm{q}}=\frac{1}{\mathrm{r}}$ are equal in magnitude but opposite in sign, then the sum of squares of these roots is equal to :
Official answer
(2)
$\displaystyle \mathrm{p}^2+\mathrm{q}^2$
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JEE Main 2018 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.